V = pi*r2*h = pi*(1.5/2)2*(100*12) cubic inches = 2120.6 cubic inches.
0.212 331 gallons per foot.
If 8 is the diameter, the formula for volume would be: pi r^2 h The radius would be half of the diameter: pi 4^2 h h is 1 foot or 12 inches pi 4^2 * 12 = 603.19 in^3 of water per foot.
10.4448, assuming 16" inside diameter. 16" outside diameter would be slightly less.
It depends on the diameter of the straw, which varies. Multiply the diameter by 3.14 and the result by the length of the straw.
A 24-inch diameter cylinder holds 23.5 gallons of water per foot of length/height.
One foot of 3 inch pipe will hold approximately 0.625 gallons of water.
Over 9,000.
A 12 inch diameter round pipe will hold 4.89 UK gallons or 5.88 US gallons per foot.
A 5-inch pipe will hold approximately 0.36 gallons of water per linear foot. This calculation is based on the formula for calculating the volume of a cylinder (V = πr^2h), where the radius (r) is half the diameter of the pipe (2.5 inches) and the height (h) is 1 foot.
The volume of water in a 4-inch diameter, 1-foot section of pipe is 0.6528 gallons of water.
A 100-foot hose with an inside diameter of five inches can hold 102 US gallons of water.
16foot
A 100-foot pipe with an inside diameter of 12 inches has a maximum volume of about 78.54 gallons of water.
A 1-foot length of a pipe with an 1-inch internal diameter will hold pi*r2*h cubic inches where r = 0.5, h = 12 So 9.42 cubic inches.
Diameter = 1 inch so radius = 0.5 inches.Volume of cylinder = pi*r2*h = pi*(0.5)2*12 = 9.4 cubic inches, approx.
A two inch pipe can hold 0.1632 gallons per foot. It takes slightly over 6 feet of two inch pipe to hold one gallon of water.