If 8 is the diameter, the formula for volume would be:
pi r^2 h
The radius would be half of the diameter:
pi 4^2 h
h is 1 foot or 12 inches
pi 4^2 * 12 = 603.19 in^3 of water per foot.
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The volume of the pipe is 0.2078 gallon per foot of length.I have no idea how much water might be in it.
The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.
36.83 u.s. gallons of water in 1 ft. of 30" pipe
There need not be any water at all in the pipe. The capacity of the pipe is approx 3.4 Imperial gallons.
Pipe Diameter = 3 Inches = .25 Ft Area of Circle = Pi X D X D / 4 - where D is Diameter and Pi is 3.14159 Volume of Pipe = Length X Area = or= 1 Foot X Area Volume = [1 Ft] X [ Pi X .25 X .25 ] / 4 Volume = 0.049087 Ft3 If the 3-inch Pipe flows at 1 Foot per second, then it will carry 0.049087 Cubic Feet per second.