1.1199999999999999
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90 + 1 + 2 + 03 + 004 = 100
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
03
.004 + 3 + .03 = 3.034
Main program run:Job start : 6th June 1997 22:29:06Job end : 8th June 1997 03:32:17Elapsed time : 29:03:11Main memory : 212 GBAlgorithm : Borweins' 4-th order convergent algorithmVerification program run:Job start : 4th July 1997 22:11:42Job end : 6th July 1997 11:19:58Elapsed time : 37:08:16Main memory : 188 GBAlgorithm : Gauss-Legendre algorithm(Brent-Salamin)Optimized main program run:Job start : 1st August 1997 23:04:15Job end : 3rd August 1997 00:18:47Elapsed time : 25:14:32Main memory : 212 GBAlgorithm : Borweins' 4-th order convergent algorithm