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I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.

I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.

I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.

I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.

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I guess this is best solved by trial and error. Try to multiply two consecutive numbers; if the product is too low, try higher number, if the product is too high, try lower numbers. For example, 20 x 21 = 420; since this is too low, your numbers are higher than that; 30 x 31 = 930; since this is too high, your numbers are lower than that.

Q: You open a book to two facing pages The product of the two page numbers is 600 find the page numbers?

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The book is opened to pages 26, on the left, and 27, on the right. The product of 26 times 27 is 702.

They are pages 42 and 43 because the product of both numbers is 1806

42 and 43 because 42*43 = 1806

Let the page on the left be ' X '. Then the right-hand page is " X + 1'.Thus x ( x + 1 ) = 2550 = [ X squared ] plus XTry making X = 50.50 x 50 = 2500Then ( 50 x 50 ) + 50 would equal 2550Since this is true, then the pages must be numbered 50 & 51

First 9 pages = 9 digit. That leaves 142 digits. @ 2 digit per page, that is 142/2 = 71 pages with 2-digit numbers. So, 9 pages with 1-digit numbers + 71 pages with 2-digit numbers = 80 pages.

Related questions

The book is opened to pages 26, on the left, and 27, on the right. The product of 26 times 27 is 702.

They are 44 and 45.

40 & 41

The two page numbers are 64 and 65. 64 x 65 = 4160.

654798712386789

They are pages 42 and 43 because the product of both numbers is 1806

Let the two facing pages be represented by x and (x+1). Since the product of the page numbers is 1056, we have the equation x(x+1) = 1056. This simplifies to x^2 + x - 1056 = 0. By solving this quadratic equation, we find the page numbers to be 32 and 33.

52 and 53

42 and 43 because 42*43 = 1806

If one of the pages is numbered p, the other is p+1. So p*(p+1) = 420 That is, p2 + p - 420 = 0 which factorises as (p - 20)*(p + 21) = 0 That implies that p = 20 or p = -21. Assuming that pages do not have negative numbers, p = 20 and then the other page is p+1 = 21.

"Cut Numbers" by Kathy Tyers has a total of 368 pages.

Yellow pages for commercial numbers and blue pages for government numbers.