4a² - b² = (2a + b)(2a - b)
(a - b + 2)(a + b + 2)
3(4a+b+2c)
5ab-2ab+4a-b+5b = 3ab+4a+4b
(4a - 3b)(4a + 3b)
(ab/b) / (4a/5b) =(ab / b) * (5b / 4a) = (5ab2 / 4ab)= 5 / (4b)
n(2a - b)(2a + b)(4a^2 - 2ab + b^2)(4a^2 + 2ab + b^2)
(a - b + 2)(a + b + 2)
n(2a - b)(2a + b)(4a^2 - 2ab + b^2)(4a^2 + 2ab + b^2)
(a + 2 - b) (a + 2 + b)
3(4a+b+2c)
5(4a + 7)
5ab-2ab+4a-b+5b = 3ab+4a+4b
The greatest common factor (GCF) of 4a and 10a is 2a. To find the GCF, we need to identify the largest factor that both 4a and 10a have in common. In this case, both 4a and 10a can be divided by 2 and a, making 2a the greatest common factor.
(4a - 3b)(4a + 3b)
With the factor 4a plus 8b 16c you can find the answer and check it mentally. You would first have to find he product of all the numbers to find the value of the letter A.
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
(ab/b) / (4a/5b) =(ab / b) * (5b / 4a) = (5ab2 / 4ab)= 5 / (4b)