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Cecile Heidenreich
Wiki User
∙ 14y agoIt is difficult, if not impossible, to entirely factorise a purely algebraic expression, however, using the difference of two squares:
15n - 1 = a2 - b2
a2 - b2 = (a+b)(a-b)
So, 15n - 1 = (a+b)(a-b).
a = √(15n)
b = √1 = 1
∴ 15n - 1 = (√(15n)+1)(√(15n)-1).
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How do you factorise a question that already has brackets?
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
How do you factorise x plus x?
x + x = x(1+1)
How do you factorise 5A plus 10AB?
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