The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
x + x = x(1+1)
You don't. There is no way to factorise it.
6x^2 + 5x + 1 = (3x +1) (2x + 1)
(x + 2)(x + 1)
-5 -15n = 10add 5 to both sides-15n = 15divide both sides by -15n = -1
a²-a = a(a-1)
1(x2-1)
To figure out what N stands for 15n, 10 and 190 needs to be used in an equation. If the equation was 15n-10=190, you would start by adding 10 to both sides to give you 15n=200. The next step would be to divide both sides by 15 which gives you n=13.33.
t(t-1)
It could be x(1 -1) when factorised
2n2 + 15n + 7 = 2n2 + n + 14n + 7 = (2n2 + n) + (14n + 7) = n(2n + 1) + 7(2n + 1) = (2n + 1)(n + 7)
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
x + x = x(1+1)
In the same way that you would factorise any other expressions that do not contain an equality sign depending on the expressions of which none have been given.
15n + 5 or 5(3n + 1)
You could do so many. Here are some examples: 15n=105 15n+105=1005 15n-105=270 Hope this is what you were looking for. :) Good luck!