7x - y = 0 → 7x = y (add y to both sides).
You now have y = 7x where y is a function of x. For a few values of x, workout what y is and plot those points. You should see a pattern to those points and be able to join them up in the right way.
(Hint, y = 7x is a linear equation, so expect a straight line between all the points.)
If the equation is 7x - 3y = 21 then (3, 0) and (0, -7).
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
7x2-10x+3=0 (7x-3)(x-1)=0
7x + 2 = 6x + 2 if and only x = 0.
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
y = -7x 0 = -7x 0 = x x-intercept point is (0, 0).
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
If the equation is 7x - 3y = 21 then (3, 0) and (0, -7).
The equation 0 equals 0 is an identity and contributes absolutely nothing to the part of the graph that you should shade or not. The tautological statement can be ignored.
The answer is x=0
The math equation of X times 2 - 7x + 12 times 0 equals 2X - 7x.
7x - 3 = 3 Subtract 3 from both sides: 7x - 6 = 0 So a = 7 and b = -6
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
63828
x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4
7x = -3y + 12
The standard form is 7x + 2y - 3 = 0