Let's use for example only water and vinegar. I want 1 part vinegar to 2 parts water. 1:2 So I would use the same measure, for the example, 1 cup measure. So 1 cup vinegar and 2 cups water. And you have a great cleaning solution.
(1 oz divided by 50) times 2 = .04 ounces
Its a Sequence when you add 1 more number onto the last number you added on for example 1 is the first number you would add 2 which would make 3 then you would add 3 which would make 6 then you add 4 which would make 10 and so on.
$2, $1, 50c, 20c, 20c.
(-1)+(-2)=(-3) (-1)(-2)=2
25
1:2 means "1 part to 2 parts", so if the "1 part" is what you are diluting, it is actually a 1/3 dilution (one part into 3 parts total). On the other hand, 1/2 means "1 part into 2 parts total", and in the colon nomenclature that would be a 1:1 dilution.
2 times dilution from 100% acetone
1:2 dilutions
Add 2 mL of culture to 20 mL of buffer. 2/20 = 1/10
1 part of stock+ 2part of dillution
The wording is important here. If it is a 2 *in* 5 dilution, then the scientist would need 200 ml of concentrate. The best way would be to take a graduated cylinder, put about 200 ml of solvent into the cylinder. Then put in the 200 ml of concentrate. Then add enough additional solvent to make a total of 500 ml. Mix, then pour it into a labeled and dated bottle, and screw on the lid. If it is a 2 *to* 5 dilution, then you need 2/7ths concentrate, and 5/7ths solvent. One seventh of 500 ml is about 71.43, so you would need 142.86 ml of concentrate, and fill the rest with solvent until the total is 500 ml.
Isotope dilution is used to determine blood volumes in living animals by predicting their isotope numbers. An example is the radioactive isotopes have a 1/2 life and that would mean it goes down by half each time.
(1 oz divided by 50) times 2 = .04 ounces
Because you probably used a 2-fold dilution. So you need to multiply your count by 2 to get the ACTUAL amount.
1 year is 7it dog years, so that would make her about 2 1/2.
1. dilution error 2.blame the test sample 3.poor maintenance of bottles(cleaning)
10x to 1x is a 1:10 dilution Therefore, add 1 part buffer, 9 parts DI-water If 100uL is 10uL (1 part buffer) and 90uL (9 parts DI-water) Then, 200ul (100 x 2) is 20uL (1 part buffer) and 180uL (9 parts DI-water)