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The first step would be to find the equation that you are trying to solve!
you don't answer an equation, you solve an equation
Without an equality sign the given expression can't be considered to be an equation
How do you use division to solve a multiplication equation?Answer this question…
If you update the answer with the actual equation i can talk you through it. 4 + 2 =X (2 - 5 = 2
To write an equation for a given problem, first identify the unknown quantity you want to find. Then, use variables to represent the unknowns and write an equation that relates the known quantities to the unknown quantity. Solve the equation to find the value of the unknown.
To write an equation for a given problem, first identify the unknown quantity you want to find. Then, use variables to represent the unknowns and write an equation that relates the known quantities to the unknown quantity. Solve the equation to find the value of the unknown.
Without an equality sign the information given does not qualify it to be an equation
It is used to solve quadratic equations that cannot be factored. Usually you would factor a quadratic equation, identify the critical values and solve, but when you cannot factor you utilize the quadratic equation.
You need to put your equation in this form... ax2 + bx + c = 0 Then identify your a,b and c
2+2
The y-intercept (or y-intercepts) of an equation is where x = 0. Replace x with zero in the equation, and solve for y.The answer depends on what information you are given - and in what form. If the equation of the curve is given in polar coordinates or in parametric form, the process is quite different to that required when given the Cartesian equation.
Use the equation, speed = distance / time, substitute in the given information from the problem and solve it.
Solve f(x) =0 or y = 0 (depending on how the equation is given).
The first step would be to find the equation that you are trying to solve!
a promlem to solve an equation or a assigment
You need not have x in an algebraic equation. You solve whichever one is the easiest and that depends on the set of equations that you have.