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The range of a projectile is given by R=(v2/g)Sin(2Theta) so for an angle of 30 and an initial speed of 100 m/s:

R=(1002/9.8)Sin(60)=(10000/9.8)(sqr3/2)= 883.7 m

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Q: If a cannon fire a cannonball at thirty degrees and the initial speed is 100 meters per second assuming there is no wind resistance and on a level field how far does the cannonball travel?
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