29.4
Assuming that air resistance can be ignored, s = ut + 0.5gt2 where s is the distance travelled = 324 feet, u is the initial velocity = 0 ft/sec, t is the time (in seconds), and g is the acceleration due to gravity = 32 ft/sec2 Therefore 324 = 0.5*16*t2 so that t2 = 20.25 and so t = 4.5 seconds.
If you assume that the punter is in space, where there is no gravity nor air resistance, it will take 2/3 second.
initial - final / initial x 100
5
The range of a projectile is given by R=(v2/g)Sin(2Theta) so for an angle of 30 and an initial speed of 100 m/s: R=(1002/9.8)Sin(60)=(10000/9.8)(sqr3/2)= 883.7 m ^^know-it-all! :@ ^^^^^^^^^;)
49
49
9.8m/s(5)= 49
,033
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)
initial primary resistance is the first stage in revolt against the initial imposition of colonial rule. the africans ready resisted the ,imposition of colonial rule. they did not give the europeans the chance to impose their colonial policies.
how am i suppose to know
Fired ammunition from a firearm reaches a much higher initial velocity due to explosive propellant forces. In contrast, ammunition dropped from a high altitude reaches a terminal velocity where gravity pulling down is balanced by air resistance pushing up. The fired bullet maintains its higher velocity until slowed by air resistance and gravity, while dropped ammunition reaches a constant speed due to these opposing forces.
If you simply release an object, the initial velocity is always zero.
A civivlized, artistocratic man used to giving orders