29.4
Assuming that air resistance can be ignored, s = ut + 0.5gt2 where s is the distance travelled = 324 feet, u is the initial velocity = 0 ft/sec, t is the time (in seconds), and g is the acceleration due to gravity = 32 ft/sec2 Therefore 324 = 0.5*16*t2 so that t2 = 20.25 and so t = 4.5 seconds.
If you assume that the punter is in space, where there is no gravity nor air resistance, it will take 2/3 second.
initial - final / initial x 100
5
The range of a projectile is given by R=(v2/g)Sin(2Theta) so for an angle of 30 and an initial speed of 100 m/s: R=(1002/9.8)Sin(60)=(10000/9.8)(sqr3/2)= 883.7 m ^^know-it-all! :@ ^^^^^^^^^;)
49
49
,033
9.8m/s(5)= 49
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/s², the speed of the rock after 5 seconds would be 49.05 m/s.
The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.
The rock's speed after 5 seconds would be approximately 49 m/s. This is calculated using the formula v = g * t, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time elapsed (5 seconds).
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)
A pendulum will eventually come to a stop due to air resistance and friction, which absorb the pendulum's energy over time. The rate at which the pendulum's motion slows down depends on the amount of resistance it encounters and the initial energy imparted to it.
No, the acceleration is not the same for an object that is dropped and an object that is thrown. When an object is dropped, it experiences a constant acceleration due to gravity. When an object is thrown, its acceleration can vary depending on factors such as the initial velocity and direction.