If: v = u+at Then: -u = -v+at or u = v-at (by dividing all terms by -1) a = (v-u)/t t = (v-u)/a
v
s is directly proportional to t
50
2t
If: v = u+at Then: -u = -v+at or u = v-at (by dividing all terms by -1) a = (v-u)/t t = (v-u)/a
v
u = p r t r = u / p t
u = prt u = 8000 * 0.6 * 1 u = 4800
You use inverse operations !!
This formula is derived from one of the basic laws of motion; v = u + at : where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration and 't' is the time v = u + at, therefore, v - u = at : a = (v - u) ÷ t
I'm guessing you want to solve for t so: 3t-6=t-2 u bring the t from the left side and subtract it from the 3t and u get 2t b/c 3-1 is 2 2t-6=2 then u bring the 6 over to the right side and u add it to the 2 and u get 2t=8 and then u divide 8 by 2 and u get t=4 if u dont understand u shud probably go to an algebra teacher because they can explain it better
(t - 10)t=17 = 7(t - 10)t=50 = 40
s is directly proportional to t
50
Where Equals __RAverage rate of return Rt Return at time t TNumber of time points Where Equals u Average rate of return Ri i-th return n Number of observations Where Equals __RAverage rate of return Rt Return at time t TNumber of time points Where Equals u Average rate of return Ri i-th return n Number of observations
ok i can help you. 5=4t-7 ok then fist u add 7 both sides of the equation. the u get 12=4t, now u have to isolate the varible. divide 4 each side. your ansers is 3=t i hope this helps u. =]