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Since volume is defined length * width * height, this is a simple algebra problem. 18 * 12 * x = 3240. Solving for x, x = 15 in. The object being placed in the box is 9 in long, 6 in wide, and 16 in high. This object can fit in the box, but it will have to be placed on its side.

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Q: If has a box that is 18 in long and 12 in wide and has a volume of 3240 cubic in he wants to pack an object that is 9 in long 6 in wide and 16 in high will the object fit in the box?
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