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This took me a while to solve it, but I finally got the right answers. I say answers because there are only 9 unique letters, and 10 number per digit you can choose from (0-9). To do this, I'll give you a couple of hints. First, when adding two digits, what is the greatest carry over you can have? Say, you add 9 + 8, what is the carry over? Therefore, M must equal 1. In order to have a carry over, the addition of M in MORE and S in SAVE needs to add up to at least 10. What two digits can S be, then, if there were a carry over? It can be 9. That means O in MONEY can only be 0, since the carry over cannot be greater than 1, and we know that M already equals 1. Lastly, the sum of E equals Y. Therefore, Y has to be even and E equals half of Y. The sum of the E's can equal any even number between 2 and 18. By process of elimination, we can already eliminate 0, 9 and 1 for the letters S, M and O. If you want to know the answer, here it is:

0 = O

1 = M

2 = Y

3 = A (if N = 4)

4 = N (if A = 3) or A (if N = 5)

5 = N (if A = 4)

6 = E

V = 7 or 8 (opposite of R)

R = 8 or 7 (opposite of V)

S = 9

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Q: If save plus more equals money what are the numerical digits for each letter and how do you solve it?
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