The probability of tossing two heads in two coins is 0.25.
24 possible outcomes.
There are eight possible outcomes: HHH, HHT, HTT, HTH, THT, TTT, TTH, THH.
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
HHHH, HHHT, HHTT, HTTT, TTTT. Pr(HHTT) = 6/16 = 0.375
Two
The probability of tossing two heads in two coins is 0.25.
Coin 1 H T or T H Coin 2 H T or T H 4 Combining H T T H H T T H From this table the result can be 2 x H 2 x T H T or T H
When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.
50%
6/16 = 3/8
It is the event that one of the two coins lands showing tails and the other shows heads.
Sample space for two coins tossed is: HH HT TH TT Therefore at most one head is HT TH TT or 3/4 or 0.75.
1 chance in 4
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
It is 1/12.
24 possible outcomes.