1 chance in 4
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1/4
1/2 x 1/2 = 1/4
The probability is 0.25.Look at it this way--if you toss a coin twice, there are four equally-probable outcomes:tails, tailstails, headsheads, tailsheads, headsSo the probability of heads twice in a row is one in four, or 25%.the chance of tossing heads is 1/2 (50%) The chance of tossing the next heads is 1/2 (50%) 1/2 x 1/2 = 1/4 (25%)
I assume you mean what's the chance of at least two heads showing when three fair coins are tossed. There are 8 possible outcomes as each coin can either be head or tails. For 3 heads, all 3 coins must show a head → 1 success For 2 heads, one coin will be a Tail; each coin could be a tail in turn → 3 successes → Pr = (1+3)/8 = 4/8 = 1/2 If you are wanting the probability that the first TWO specific coins are heads and the last, third, coin is either, then: Pr(head) = 1/2 → Pr(1st 2 heads, 3rd anything) = 1/2 × 1/2 × 1 = 1/4
6/36