1/4
1/2 x 1/2 = 1/4
The probability is 0.25.Look at it this way--if you toss a coin twice, there are four equally-probable outcomes:tails, tailstails, headsheads, tailsheads, headsSo the probability of heads twice in a row is one in four, or 25%.the chance of tossing heads is 1/2 (50%) The chance of tossing the next heads is 1/2 (50%) 1/2 x 1/2 = 1/4 (25%)
I assume you mean what's the chance of at least two heads showing when three fair coins are tossed. There are 8 possible outcomes as each coin can either be head or tails. For 3 heads, all 3 coins must show a head → 1 success For 2 heads, one coin will be a Tail; each coin could be a tail in turn → 3 successes → Pr = (1+3)/8 = 4/8 = 1/2 If you are wanting the probability that the first TWO specific coins are heads and the last, third, coin is either, then: Pr(head) = 1/2 → Pr(1st 2 heads, 3rd anything) = 1/2 × 1/2 × 1 = 1/4
6/36
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
The probability of 2 coins both landing on heads or both landing on tails is 1/2 because there are 4 possible outcomes. Head, head. Head, tails. Tails, tails. Tails, heads. Tails, heads is different from heads, tails for reasons I am unsure of.
One out of every four flips
The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once! Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25. If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.
The probability that 2 flipped coins both come up heads is 0.52 or 0.25
1/2
If both tosses are fair, the probability of that outcome is one in four.
1/4
one fourth
These are all independent events. So the probability of them all happening is the product of the probabilities of each one of them happening. The desired probability is (2/6)*(1/2)*(1/2)=1/12
1/2 x 1/2 = 1/4
One in four. 1:4. The probability of getting heads when a fair coin is tossed is: P(H) = 1/2. The probability of getting heads on a second toss is: P(H) = 1/2, this result is independent of the result of the first toss. The probability of having both events happen (heads on the first and heads on the second toss) is: P(H1UH2) = (1/2)∙(1/2) = 1/4 = 0.25 = 0.25%