y=1/3x
x=-18
y=1/3(-18)
y=-6
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To find two numbers that add to 3 and multiply to 18, we can set up a system of equations. Let's call the two numbers x and y. We have the equations x + y = 3 and x * y = 18. By solving this system, we can find that the numbers are 1.5 and 12.
Sum of digits x+y=8 Two digit no assume as 10x+y It is given that 10x+y+18=10y+x 9x-9y+18=0 x-y=-18/9 x-y= -2 Equate both x+y-8=x-y+2 2y=10 y= 5 Substitute this y in x+y x+5=8 x=3 So 35 is original two digit no Reversed new no is 53
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
Let's denote the two numbers as x and y. We can set up a system of equations: x + y = 18 and x - y = 4. By solving this system simultaneously, we can find that x = 11 and y = 7. Therefore, the two numbers that add up to 18 and subtract to 4 are 11 and 7.