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We treat this as a permutations and combinations problem... as there are two possible 'rules' involved.
If we are allowed to repeat a digit (such as 456537 - which as two 5s in it) then there are 9 options for every digit. So 9 x 9 x 9 x 9 x 9 x 9 = 531441 different six-digit numbers from a choice of 9.
If we cannot repeat a digit, as we did above, thee need to pick the first number - and it can be any of the 9.. then the second number can be any of 8, and the third can be any of 7 and so on.... this is called permutations and we end up with a multiplication like before but with each figure lower than the one before it.... 9 * 8 * 7 * 6 * 5 * 4 = 60480 different permutations of six digits from a choice of 9.
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If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many different combinations are possible multiplying 8 different 7 digit numbers?
56 combinations. :)
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many 4 digit combanations using the numbers 1-7?
There are 840 4-digit combinations without repeating any digit in the combinations.
How many possible 4 digit combinations are there using 0-9. how many different combination codes are possible?
There are 210 4 digit combinations and 5040 different 4 digit codes.
