Well, assuming you mean the value of the coins together is $20, and knowing that the value of a dime is $0.10 and that of a quarter is $0.25, then if we call the number of dimes 'd' and the number of quarters 'q', we can set up the following equations:
d + q = 100
0.10d + 0.25q = 20
Then you can obtain the number of dimes and quarters by solving this series of linear equations.
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
8 of them.
The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?
dimes : all coins = 6 : 12+6+18 = 6 : 36 = 1×6 : 6×6 = 1 : 6 Dimes are ⅙ of all coins.
To make $2.50 from quarters (worth 25 cents) and dimes (worth 10 cents), we can set up a system of equations. Let q represent the number of quarters and d represent the number of dimes. The equations would be 25q + 10d = 250 (representing the total value in cents) and q + d = 25 (representing the total number of coins). Solving these equations simultaneously, we find that there are 6 ways to make $2.50 using quarters and dimes.
If Keoki has 14 quarters and 8 dimes (for a total of 22 coins), she has $3.50 and $0.80 or $4.30 in coins. If Keoki has 15 quarters and 7 dimes (for a total of 22 coins), she has $3.75 and $0.70 or $4.45 in coins. If Keoki has 22 coins that are all dimes and quarters and their value in total is $4.35 as asked, there isn't a combination of coins that will permit her to have both 22 coins and $4.35 worth of coins.
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
8 quarters, 5 dimes
16 % of the coins are dimes. 4 of a total of 25.
8 of them.
The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?
Eighteen
dimes : all coins = 6 : 12+6+18 = 6 : 36 = 1×6 : 6×6 = 1 : 6 Dimes are ⅙ of all coins.
If you have 37 coins and 18 are quaters ($4.50) and 19 are dimes ($1.90) then the amount is $6.40.
To make $2.50 from quarters (worth 25 cents) and dimes (worth 10 cents), we can set up a system of equations. Let q represent the number of quarters and d represent the number of dimes. The equations would be 25q + 10d = 250 (representing the total value in cents) and q + d = 25 (representing the total number of coins). Solving these equations simultaneously, we find that there are 6 ways to make $2.50 using quarters and dimes.
15 quarters, 3 dimes
The coins in a cash register amount to $12.50. One coin combination that would produce this total is 40 quarters, 19 dimes, 2 nickels, and 50 pennies. Another combination is 20 quarters, 50 dimes, 45 nickels, and 25 pennies.