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Label the angles of the triangle A, B, and C. Label the side opposite angle A side a, the one opposite angle B side b, and the one opposite angle C side c.

Let's say you want to solve for angle A, you use the law of cosines:

a^2=b^2+c^2-2bcCosA

CosA is the "variable" in this equation, so isolate this. When you have that, you'll have some number (let's call it D) equal to CosA:

D=CosA

Use the inverse Cos function to find the measure of the angle:

Cos^-1(D)=A

And you have the measure of angle A.

From here you can either use the law of cosines again to find a second angle and then the third, though the easier route is usually to just use the law of sines for find the second angle and then the fact that all three angles add to 180 to find the third.

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Q: If you have all sides of a triangle how do you use the law of cosines to solve the angles?
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