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In solving the quadratic equation x2 plus 12x - 5 equals 0 what value would complete the square?
Wiki User
∙ 14y ago
x2 + 12x - 5 = 0
x2 + 12x - 5 + 5 = 0 + 5
x2 + 12x = 5
x2 + 12x + (12/2)2 = 5 + (12/2)2
x2 + 12x + (6)2 = 5 + 36
(x + 6)2 = 41 (square root of both sides)
x + 6 = ± √41
x + 6 - 6 = -6 ± √41
x = -6 ± √41
x ≈ -6 + 6.4 = -0.4
x ≈ -6 - 6.4 = -12.4
Wiki User
∙ 14y ago
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