no
Yes
Yes. However, because the distribution is symmetric about 0, some tables give only positive values for z.
Nothing particular, since z is symmetric about zero. Half the time z is negative.
symmetric about the y-axis symmetric about the x-axis symmetric about the line y=x symmetric about the line y+x=0
Since the normal distribution is symmetric, the area between -z and 0 must be the same as the area between 0 and z. Using this fact, you can simplify this problem to finding a z such that the area between 0 and z is .754/2=.377. If you look this value up in a z-table or use the invNorm on a calculator, you will find that the required value of z will be 1.16. Therefore, the area between -1.16 and 1.16 must be approximately .754.
symmetric nephrograms
Yes. However, because the distribution is symmetric about 0, some tables give only positive values for z.
A=r mod z R= a relation which is reflexive symmetric but not transitive
The standard Normal distribution is symmetric about 0 and so 50% of the Z values are positive.
Nothing particular, since z is symmetric about zero. Half the time z is negative.
Equality is a relationship that is REFLEXIVE: x = x SYMMETRIC: If x = y the y = x TRANSITIVE: If x = y and y = z then x = z.
for any real numbers x, y and z: REFLEXIVE PROPERTY; x=x SYMMETRIC PROPERTY; if x=y, then y=x TRANSITIVE PROPERTY; if x=y and y=z then x=z
symmetric about the y-axis symmetric about the x-axis symmetric about the line y=x symmetric about the line y+x=0
The tables for Z-scores are given in the form of P = Prob(Z < z) for various value of P and z. Since Prob(Z > z) = 0.93 > 0.5, then by symmetry, z < 0. So suppose z = -a where a > 0 Now Prob(Z > -a) = 0.93 is the same as Prob(Z < a) = 0.93 [because the standard Normal is symmetric]. therefore, from the tables, a = 1.4758 (approx) and so z = -1.4758 (approx).
Yes a flower is symmetric.
The answer is not avalible
Symmetric
yes, it is both symmetric as well as skew symmetric