Nothing particular, since z is symmetric about zero. Half the time z is negative.
If a random variable X has a Normal distribution with mean m and standard deviation s, then z = (X - m)/s has a Standard Normal distribution. That is, Z has a Normal distribution with mean 0 and standard deviation 1. Probabilities for a general Normal distribution are extremely difficult to obtain but values for the Standard Normal have been calculated numerically and are widely tabulated. The z-transformation is, therefore, used to evaluate probabilities for Normally distributed random variables.
The answer will depend on the underlying distribution for the variable. You may not simply assume that the distribution is normal.
If you have a variable X that is normally distributed with mean m and variance s2 then the z-score, Z = (X - m)/s.Z has a standard Normal distribution.
The standard normal distribution is a special case of the normal distribution. The standard normal has mean 0 and variance 1.
The area under the standard normal curve is 1.
It is the Standard normal variable.
Use the context: if the variable should be greater than the mean then z is positive and if less than the mean, it should be negative.
It is 0.5
About half the time.
None.z-scores are linear transformations that are used to convert an "ordinary" Normal variable - with mean, m, and standard deviation, s, to a normal variable with mean = 0 and st dev = 1 : the Standard Normal distribution.
If a variable X, is distributed Normally with mean m and standard deviation s thenZ = (X - m)/s has a standard normal distribution.
An ordinary variable is standardised by taking a linear transformation of it such that the new variable has standard properties. For example, if X is a Gaussian (Normal) variable with mean mu and standard deviation sigma, then Z = (X - mu)/sigma has a Normal distribution with mean 0 and SD = 1: it has been standardised.
0.636 approx.
It is 0.1587
Yes, to approximately standard normal.If the random variable X is approximately normal with mean m and standard deviation s, then(X - m)/sis approximately standard normal.
The z-score is used to convert a variable with a Gaussian [Normal] distribution with mean m and standard error s to a variable with a standard normal distribution. Since the latter is tabulated, the probability of an outcome as extreme or more compared to the one observed is easily obtained.
It is 1.17