Yes.
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Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
No, 32715 is not divisible by 2 because a number is divisible by 2 if it ends in 0, 2, 4, 6, or 8. In this case, the last digit of 32715 is 5, which is not divisible by 2. Therefore, 32715 is not divisible by 2.
No, any number divisible by 2 will end in 2, 4, 6, 8, or 0. In this instance, 3543/2 = 1771.5.
If the last digit (6) is divisible by 2 - that is, it is 0, 2, 4, 6 or 8 then the number is divisible by 2. Note that this rule cannot be used to check for divisibility by other numbers.