To determine if 441 is divisible by 3, you can add the digits of 441 together: 4 + 4 + 1 = 9. Since 9 is divisible by 3, then 441 is also divisible by 3. This is because a number is divisible by 3 if the sum of its digits is divisible by 3.
1, 3, 7, 9, 21, 49, 63, 147, 441
It i.s easy to see that 147 is composite. Simply add up the digits. 1 + 4 + 7 = 12. 12 is divisible by three, therefore 147 is divisible by three ! This trick also works for division by nine.
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It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
1, 3, 49, and 147
1, 3, 49, and 147
To determine if 441 is divisible by 3, you can add the digits of 441 together: 4 + 4 + 1 = 9. Since 9 is divisible by 3, then 441 is also divisible by 3. This is because a number is divisible by 3 if the sum of its digits is divisible by 3.
All multiples of 147 are divisible by 147: 147, 294, 441, 588, 735, ...
147 has factors other than 1 and itself, so it is not a prime number. For example, 147 is divisible by 3. (You can quickly check this by adding up the digits of 147: 1 + 4 + 7 = 12. If the sum of the digits is divisible by 3, so is the number.) Therefore, 147 is a composite number.
1, 3, 7, 9, 21, 49, 63, 147, 441
No, 3 is a factor of both. Note that the digits of 120 add up to 3 and those of 147 add up to 12. Both are multiples of 3 so the numbers 120 s and 147 are divisible by 3 and not relatively prime
Two numbers: 126 and 147
It is composite. It is evenly divisible by 3.
Yes. 1,323 / 9 = 147
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
Whole numbers, composite numbers, odd numbers, numbers divisible by 3, and many more.