Yes. It is a multiple of 1, as are all integers.
Yes. It is a multiple of 1, as are all integers.
Yes. It is a multiple of 1, as are all integers.
Yes. It is a multiple of 1, as are all integers.
You should subtract in powers with the base of 3 The smallest number less than 23 is 32 or 9 The smallest multiple of 9 less than 23 is 18 ( 2 X 9 ), so 2 is your first number 23 - 18 = 5 The smallest number less than 5 is 31 or 3 The smallest multiple of 3 less than 5 is 1 ( 1 X 3 ), so 1 is your next number 5 - 3 = 2 So the answer is 212
The largest 3 digit number which when divided by 69 and 12 to give a remainder of 1 is 829. What we want is one more than a common multiple of 69 and 12. The common multiples of 69 and 12 are the multiples of their least common multiple: 69 = 3 x 23 12 = 2^2 x 3 → lcm = 2^2 x 3 x 23 = 276 The largest multiple of 276 which is a 3 digit number: 999 ÷ 276 = 3 r 171 → largest 3 digit multiple of 276 is 3 × 276 = 828 → the required number is 828 + 1 = 829.
2 x 3 x 4 - 1. 2 times 3 is 6, times 4 is 24, minus 1 is 23
To find the least common multiple of numbers there are two methods. #1 You list the multiples of each number. Identify the least number that is on both lists. #2 Find the common factors of the numbers. In this case their are no common factors because 23 is prime. Here's what you do: 1. Find the prime factorization of 21 and 23. 21=7*3 23=23 2. Take the factors and multiply them all together once because each one is only shown once. 7*3*23=? 3. 7 times 3 equals 21 times 23 is 483. LCM=483
The Least Common Multiple (LCM) for 3 23 is 69.
You should subtract in powers with the base of 3 The smallest number less than 23 is 32 or 9 The smallest multiple of 9 less than 23 is 18 ( 2 X 9 ), so 2 is your first number 23 - 18 = 5 The smallest number less than 5 is 31 or 3 The smallest multiple of 3 less than 5 is 1 ( 1 X 3 ), so 1 is your next number 5 - 3 = 2 So the answer is 212
It is 1/3.It is 1/3.It is 1/3.It is 1/3.
The least common multiple of 3 , 23 = 69
3 - 2 and 2/3 = 1/3
The largest 3 digit number which when divided by 69 and 12 to give a remainder of 1 is 829. What we want is one more than a common multiple of 69 and 12. The common multiples of 69 and 12 are the multiples of their least common multiple: 69 = 3 x 23 12 = 2^2 x 3 → lcm = 2^2 x 3 x 23 = 276 The largest multiple of 276 which is a 3 digit number: 999 ÷ 276 = 3 r 171 → largest 3 digit multiple of 276 is 3 × 276 = 828 → the required number is 828 + 1 = 829.
2.3 = 23/10 and reduces to: 2 3/10
1 is a multiple of only 1 . Every number that's not 1 is a multiple of at least 2 numbers. 2 and 3 are multiples of 2 numbers. 4 is a multiple of 3 numbers.
1, 2 and 3
Because this equation has complex roots, you need to use complex numbers. The easiest way is to use the quadratic formula This will give you (-3 +/- (-23)1/2 ) / 8. Thus, the answer is -3/8 + i(23)1/2 and -3/8 - i(23)1/2 Giving you factors of (x + (3/8 + i(23)1/2 ))(x + (3/8 - i(23)1/2))
It is: (3*7)+2 = 23
The LCM of 23 and 7 is 161. The LCM of 2, 3 and 7 is 42.
2 is 1 and three is 1