No, geometric, common ratio 2
612
3 1.5
96 (each number is twice the previous)
Sum of 1st 2 terms, A2 = 2 + 4 = 6 Sum of 1st 3 terms, A3 = 2 + 4 + 6 = 12 Sum of 1st 4 terms A4 = 2 + 4 + 6 + 12 = 20 you can create a formula for the sum of the 1st n terms of this sequence Sum of 1st n terms of this sequence = n2 + n so the sum of the first 48 terms of the sequence is 482 + 48 = 2352
You are adding by 12. 12 + 12 = 24 24 + 12 = 36 36 + 12 = 48
612
96 because you are multiplying by 2, so 6 x 2 is 12, 12 x 2 is 24, 24 x 2 is 48, 48 x 2 is 96, etc.
3 1.5
The common ratio is 2.
A single number, such as 4642142824816 does not constitute a sequence.
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
96 (each number is twice the previous)
Sum of 1st 2 terms, A2 = 2 + 4 = 6 Sum of 1st 3 terms, A3 = 2 + 4 + 6 = 12 Sum of 1st 4 terms A4 = 2 + 4 + 6 + 12 = 20 you can create a formula for the sum of the 1st n terms of this sequence Sum of 1st n terms of this sequence = n2 + n so the sum of the first 48 terms of the sequence is 482 + 48 = 2352
It could be either. The answer depends on how many terms if any are between 48 and 192.
They are: 12, 24, 36 and 48
You are adding by 12. 12 + 12 = 24 24 + 12 = 36 36 + 12 = 48
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48