No, geometric, common ratio 2
612
3 1.5
96 (each number is twice the previous)
Sum of 1st 2 terms, A2 = 2 + 4 = 6 Sum of 1st 3 terms, A3 = 2 + 4 + 6 = 12 Sum of 1st 4 terms A4 = 2 + 4 + 6 + 12 = 20 you can create a formula for the sum of the 1st n terms of this sequence Sum of 1st n terms of this sequence = n2 + n so the sum of the first 48 terms of the sequence is 482 + 48 = 2352
You are adding by 12. 12 + 12 = 24 24 + 12 = 36 36 + 12 = 48
612
96 because you are multiplying by 2, so 6 x 2 is 12, 12 x 2 is 24, 24 x 2 is 48, 48 x 2 is 96, etc.
3 1.5
The common ratio is 2.
A single number, such as 4642142824816 does not constitute a sequence.
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
96 (each number is twice the previous)
It could be either. The answer depends on how many terms if any are between 48 and 192.
Sum of 1st 2 terms, A2 = 2 + 4 = 6 Sum of 1st 3 terms, A3 = 2 + 4 + 6 = 12 Sum of 1st 4 terms A4 = 2 + 4 + 6 + 12 = 20 you can create a formula for the sum of the 1st n terms of this sequence Sum of 1st n terms of this sequence = n2 + n so the sum of the first 48 terms of the sequence is 482 + 48 = 2352
They are: 12, 24, 36 and 48
You are adding by 12. 12 + 12 = 24 24 + 12 = 36 36 + 12 = 48
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48