Yes: 3 x 78 = 234
No, 78 is not evenly divisible by 9.
39, 78, 117, 195, 312 and 936 are divisible by three.
2 x 3 x 13 is the answer. 78 is easily divisible by 2 so that makes 2 and 39. Then 39 becomes 3 and 13.
To determine if a number is divisible by 4, we look at the last two digits of the number. In this case, the last two digits of 234678 are 78. For a number to be divisible by 4, the last two digits must form a number that is divisible by 4. Since 78 is not divisible by 4, 234678 is not divisible by 4.
78 is evenly divisible by 1, 2, 3, and 13.
All multiples of 78 are divisible by it. For example ( 78 X 2, 156) or (78 x 3 , 234) etc.
To determine if 78 is a multiple of 3, we can use the divisibility rule for 3. The rule states that if the sum of the digits of a number is divisible by 3, then the number itself is also divisible by 3. In this case, 7 + 8 = 15, which is divisible by 3. Therefore, 78 is indeed a multiple of 3.
Both.
Yes: 3 x 78 = 234
No, 78 is not evenly divisible by 9.
No. 78 is not divisible by 2356.
2, 3, 6, and 39
yes to both.
For a number to be divisible by 6, it has to be divisible by 2 and 3, because 2*3=6.In other words, we could divide the number we're factorising (78) by the prime factors of the number we're testing (6, which is 2*3). We start by dividing by 2, because we know 78 is even: 78/2=39. Then, we divide the new number by the other prime factor - 3. 39/3=13 13 is a whole number with no remainders, therefore we can say that 78 is divisible by 6, and therefore 6 is a factor of 78. (6*13=78)
78, 156, 234 and so on.
To determine whether 3 is a multiple of 78, divide 78 by 3. You should get 78 / 3 = 26. So 3 is a multiple of 78. Another way to work out this problem is to add up the digits of 78. 7 + 8 = 15, which is divisible by 3. So 3 is a multiple of 78.