No, 7 is not divisible by 3. In division, when a number is divisible by another number, it means that the division results in a whole number without any remainder. When you divide 7 by 3, you get 2 with a remainder of 1, which means 7 is not divisible by 3.
18444 is divisible by 3: 18444/3 = 6148. 18444 is not divisible by 5: 18444/5 = 3688.8 18444 is divisible by 6: 18444/6 = 3074 18444 is not divisible by 7: 18444/7 = 2634.857142 18444 is not divisible by 10: 18444/10 = 1844.4
Yes, 75 is divisible by 3. A number is divisible by 3 if the sum of its digits is also divisible by 3. In this case, 7 + 5 = 12, and 12 is divisible by 3 (12 ÷ 3 = 4), so 75 is divisible by 3.
Oh, what a lovely question! Let's see, we can find the numbers divisible by 3 first, which are 33 numbers, and the numbers divisible by 7, which are 14 numbers. But wait, some numbers are divisible by both 3 and 7, so we must be careful not to count them twice. In the end, there are 47 numbers between 1 and 100 that are divisible by 3 or 7. Happy counting!
2463. The trick is that a number is divisible by 3 if and only if the sum of its digits is divisible by 3. 1+3+2+4 = 10 (not divisible by 3), while 2+4+6+3 = 15 (divisible by 3).
The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.
3*21 = 63 so 63 is divisible by 3 7*9 = 63 so 63 is divisible by 7.
Yes, 774 is divisible by 3. To determine this, you can add the digits of the number: 7 + 7 + 4 = 18. Since 18 is divisible by 3, it follows that 774 is also divisible by 3.
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
NO. 313 is not divisible by 3.A number is divisible by 3 if the sum of the digits is divisible by 3.313 = 3 + 1 + 3 = 7Note: 7 not divisible by 3 thus, 313 is not divisible by 3.
Not evenly. An easy way to tell is that its digits add up to 7, a number which is not divisible by 3.
Because 21 is a multiple of 1, 3, 7 and 21.
To show that the product of 56 and 39 is exactly divisible by 21, you can check if both numbers are divisible by the prime factors of 21, which are 3 and 7. Since 56 is divisible by 7 (56 ÷ 7 = 8) and 39 is divisible by 3 (39 ÷ 3 = 13), their product will also be divisible by both 3 and 7. Therefore, 56 x 39 is divisible by 21.
18444 is divisible by 3: 18444/3 = 6148. 18444 is not divisible by 5: 18444/5 = 3688.8 18444 is divisible by 6: 18444/6 = 3074 18444 is not divisible by 7: 18444/7 = 2634.857142 18444 is not divisible by 10: 18444/10 = 1844.4
No; 1+7+3+5= 16 16 isn't divisible by 3.
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.
1, 2, 7, 3 and 6 are not divisible by 4 and/or 9. 12736 is divisible by 4 but not by 9.
To determine if 6547 is divisible by 3, you can sum the digits: 6 + 5 + 4 + 7 = 22. Since 22 is not divisible by 3, 6547 is also not divisible by 3.