Yes.
Sum of the digits in the odd positions = 8 + 2 = 10
Sum of the digits in the even positions = 4 + 6 = 10
The difference of these sums = 10 - 10 = 0
Since this number leaves a remainder of 0 when divided by 11, the original number is divisible by 11.
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766 x 11 = 8426
No. For instance, 101 is not divisible by 11.
if the difference of the sum at the alternate places is divisible by 11 then it is divisible by 11
No.
8 of the numbers less than 660 are divisible by 5 and 11 but not 3. All numbers divisible by 5 and 11 are multiples of their lcm; lcm(5, 11) = 55 All numbers divisibile by 5, 11 and 3 are multiples of their lcm; lcm(5, 11, 3) = 165 659 ÷ 55 = 11 54/55 → 11 numbers less than 660 are divisible by 5 and 11 659 ÷ 165 = 3 164/165 → 3 numbers less than 660 are divisible by 5, 11 and 3 → of the 11 numbers less than 660 divisible by 5 and 11, 3 are also divisible by 3 → 11 - 3 = 8 numbers less than 660 are divisible by 5 and 11 but not 3,.