Yes. The result is 19.
1, 5, 19, 95 There are an infinite amount of numbers divisible by 95
285 is divisible by these numbers: 1, 3, 5, 15, 19, 57, 95, 285.
Yes, 380 is divisible by these numbers: 1, 2, 4, 5, 10, 19, 20, 38, 76, 95, 190, 380.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
Well, honey, it's simple math. Prime numbers are only divisible by 1 and themselves. If you can divide a number by anything other than 1 and itself, it ain't prime. So, if you try dividing 32 by 2, 4, 8, or 16, and 95 by 5 or 19, you'll see they ain't prime, sweetie.
1, 5, 19, 95 There are an infinite amount of numbers divisible by 95
95 is divisible by 5, so no, it is not
95 95/5=19
1, 5, 19, 95
Out of that list, only 5.
All multiples of 95, which is an infinite number.
Actually, 95 is not a prime number because it is divisible by 5.
No, 95 isn't prime because it is divisible by 5 and 19.
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).
32 ends in a 2 so is divisible at least by 2 [32/2 = 16] 95 ends in a 5 so is divisible at least by 5 [95/5 = 19]
One number that it's divisible by is 5. Any number that ends in 0 or 5 is divisible by 5. 475/5 = 95
95 is divisible by 5 (as is any number ending in 5) so it is composite