1, 5, 19, 95 There are an infinite amount of numbers divisible by 95
285 is divisible by these numbers: 1, 3, 5, 15, 19, 57, 95, 285.
Yes, 380 is divisible by these numbers: 1, 2, 4, 5, 10, 19, 20, 38, 76, 95, 190, 380.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
To determine if 32 and 95 are not prime numbers without finding their factors, you can use the divisibility rules. For 32, you can see that it is divisible by 2 and 4 since it ends in an even number and its last two digits form a number divisible by 4. For 95, it is divisible by 5 since it ends in 5. These divisibility rules indicate that both 32 and 95 are not prime numbers.
1, 5, 19, 95 There are an infinite amount of numbers divisible by 95
95 is divisible by 5, so no, it is not
95 95/5=19
1, 5, 19, 95
Out of that list, only 5.
All multiples of 95, which is an infinite number.
Actually, 95 is not a prime number because it is divisible by 5.
No, 95 isn't prime because it is divisible by 5 and 19.
32 ends in a 2 so is divisible at least by 2 [32/2 = 16] 95 ends in a 5 so is divisible at least by 5 [95/5 = 19]
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).
One number that it's divisible by is 5. Any number that ends in 0 or 5 is divisible by 5. 475/5 = 95
95 is divisible by 5 (as is any number ending in 5) so it is composite