No. Assuming no parentheses, a/b/c = (a/b)/c = a/bc. For example, 1/2/3 = (1/2)/3 = 1/6.
If there are parentheses for the last 2 terms, such as a/(b/c), then it is ac/b.
Similarly, if you see it written out as a complex fraction with the a on the top half and the b/c in the bottom half, then it is the same as ac/b.
If AC plus CB equals AB and AC is equal to CB, then point C is the midpoint of segment AB. This means that point C divides the segment AB into two equal parts, making AC equal to CB. Therefore, point C is located exactly halfway between points A and B.
Sadly, parentheses are not retained when the question is stored,so we can't tell where you meant for them to be.Here are a couple of alternatives:(A/B)/C = A/BCA/(B/C) = A x C/B = AC/B
Difficult to tell when you cannot use parentheses. a*(b+c) or a(b+c) = ab + ac This is known as the distributive property of multiplication over addition.
ab x ac = ab - ac
A statement that two ratios are equal; such as A over B equals C over D
A mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/C
There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.
If a < b, and c is positive, then ac < bcIf a < b, and c is negative, then ac > bc(inequality swaps over!)
If AC plus CB equals AB and AC is equal to CB, then point C is the midpoint of segment AB. This means that point C divides the segment AB into two equal parts, making AC equal to CB. Therefore, point C is located exactly halfway between points A and B.
Sadly, parentheses are not retained when the question is stored,so we can't tell where you meant for them to be.Here are a couple of alternatives:(A/B)/C = A/BCA/(B/C) = A x C/B = AC/B
If point C is between points A and B, then the distance from A to B (AB) is equal to the sum of the distances from A to C (AC) and from C to B (CB). This can be expressed mathematically as AB = AC + CB. Therefore, if you know the lengths of AC and CB, you can find AB by adding those two lengths together.
The distributive property states that for any real numbers a, b, and c, the product of a and the sum (or difference) of b and c is equal to the sum (or difference) of the products of a and b and a and c. In mathematical terms, it can be written as a(b + c) = ab + ac or a(b - c) = ab - ac, where a, b, and c are real numbers. This property is fundamental in algebraic operations and simplifying expressions.
Well. Multiply both sides by 'c'. After that you should have something like ac=b-4 then you add 4, to get this result 4+ac=b.
Difficult to tell when you cannot use parentheses. a*(b+c) or a(b+c) = ab + ac This is known as the distributive property of multiplication over addition.
ab x ac = ab - ac
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
We can use the identity ((a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + ac + bc)). Given that (a + b + c = 12) and (a^2 + b^2 + c^2 = 64), we can substitute these values into the identity: [ 12^2 = 64 + 2(ab + ac + bc). ] Calculating (12^2) gives us 144, so: [ 144 = 64 + 2(ab + ac + bc). ] Subtracting 64 from both sides gives us: [ 80 = 2(ab + ac + bc). ] Dividing by 2, we find: [ ab + ac + bc = 40. ] Thus, the value of (ab + ac + bc) is 40.