Sadly, parentheses are not retained when the question is stored,
so we can't tell where you meant for them to be.
Here are a couple of alternatives:
(A/B)/C = A/BC
A/(B/C) = A x C/B = AC/B
For the equation A/B = C/D. Multiply both sides by B: A*B/B = C*B/D, then multiply both sides by D: A*B*D/B = C*B*D/D, then simplify (the B's cancel and the D's cancel): A*D = C*B
30.. B
As A/B=C/D , So B=(A*D)/C
No. But multiplication is distributive over addition. This means that for any numbers A, B, and C A x (B + C) = (A x B) + (A x C). If addition were distributive over multiplication, that would mean that A + (B x C) = (A + B) x (A + C) which is not true.
No. Assuming no parentheses, a/b/c = (a/b)/c = a/bc. For example, 1/2/3 = (1/2)/3 = 1/6. If there are parentheses for the last 2 terms, such as a/(b/c), then it is ac/b. Similarly, if you see it written out as a complex fraction with the a on the top half and the b/c in the bottom half, then it is the same as ac/b.
b+c^2 There is no way to simplify that.
To simplify the expression (3b + 11c - 4b - c), first combine the like terms. For the terms with (b), subtract (4b) from (3b) to get (-b). For the terms with (c), subtract (c) from (11c) to get (10c). Thus, the simplified expression is (-b + 10c).
(bc)2
You can't simplify that any more.
You can't simplify that any more.
For the equation A/B = C/D. Multiply both sides by B: A*B/B = C*B/D, then multiply both sides by D: A*B*D/B = C*B*D/D, then simplify (the B's cancel and the D's cancel): A*D = C*B
A over B+ C over B=A+C over B=N
1/a = 1/b: cross multiplying gives a = b
30.. B
As A/B=C/D , So B=(A*D)/C
a*(b-c) = a*b - a*c
The law that states multiplication can be distributed over addition is known as the Distributive Property. It expresses the principle that for any numbers (a), (b), and (c), the equation (a \times (b + c) = (a \times b) + (a \times c)) holds true. This property allows us to simplify expressions and solve equations by distributing the multiplication across the terms inside the parentheses.