For a given perimeter, the circle has the largest area possible.
The circle and the square are the two parents.
Area of a circle in square inches = pi*radius2 in inches
21.5%
If the circle is inside the square, four.
Of course, it is not possible !
A circle with a diameter of 2 is the guiding cynosure when Pi is the square of all possible circles: If the square root of Pi defines the side of a square and that square can be inscribed within a circle or enclose a circle, then the diameters of all possible circles between the largest and smallest include the circle of which Pi is its perfect square (a diameter of 2).
For a given perimeter, the circle has the largest area possible.
The is not stated that the circle inside the square was the greatest possible circle, so all one can say is 8pi at most.
Let the side of square be of length '2a' For the largest circle carved out of the square sheet, radius will be 'a' and hence the required area of circle = PI(a2)
A circle.
Yes it is possible just press, Square,Square,Circle,Triangle.
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This depends on the circle you're talking about. A theoretical circle and square most certainly could have the same area. If the circle's radius is 1, then the square's length and width would be √π. The problem here is actually in creating such a measurement in a finite number of steps. Because pi is a transcendental number, that is not possible.
90 square inches
Use as much of the string as is possible to make the circle. In the limit, the circumference of the circle is 50 inches and the perimeter of the square is 0. This gives a circle with an area of 198.94 sq inches and a square with an area of 0 sq inches. Any string moved from the circle to the square will reduce the total area.
The answer depends on the relationship between the square and the circle. For example, is the circle inscribed in the square or the square in the circle or something else?