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Q: Is sss a way to find if triangles are similar?

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Yes.

A triangle that can be made in more than one way

No. Equilateral triangles have 60o angles. There is no way to build a right-angle triangle with sides of equal length.

The way you do trigonometry is by working with triangles. Trigonometry is a math class that is taught in high school and usually followers algebra and geometry.

one way is to use the corresponding parts. if they are congruent then the two triangles are congruent. i don't know any other ways without seeing the triangles or any given info. sorry i couldn't help more.

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depends on what you have.... one way is to see that the the triangles share two same angles, and one side with equal length...

Here guys Thanks :D Congruent triangles are similar figures with a ratio of similarity of 1, that is 1 1 . One way to prove triangles congruent is to prove they are similar first, and then prove that the ratio of similarity is 1. In these sections of the text the students find short cuts that enable them to prove triangles congruent in fewer steps, by developing five triangle congruence conjectures. They are SSS! , ASA! , AAS! , SAS! , and HL ! , illustrated below.

Yes, AAA is a way to show that triangles are similar. Note, however, that AAA is not a way to show that triangles are congruent.

Yes.

They are both closed figures

They can be constructed in more than one way. They have fractional dimension. They are self-similar. They are constructed by removing small triangles from a big triangle.

The only general way is to divide the pentagon into three triangles, calculate the areas of the triangles and add them together.

One way is they both are triangles and have 3 sides.

4 triangles make 1 hexagon. (easy way to find out how many triangles there are in a polygon- take number of sides of the polygon, subtract 2 from it, that's your answer!)

Triangles are not equal to each other in the same way that 5 = 5 or 23 = 8 + 15 because they are not discrete values. Congruent is a similar term to equivalent, which allows comparison.

Such as? If you can break the shape up into triangles you can find the area that way. Or, you can get into calculus-based equations if you have an equation for the random shape.

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