3a + 2b is an expression in algebra. If you make 3a + 2b equal to something then you can find the values of "a" and "b" Lets say you make 3a + 2b equal to 23 3a + 2b = 23 Now find "a" and "b" to make this equation true... 3(5) + 2(4) = 23 15 + 8 = 23 23 = 23 Correct So in this case a=5 and b=4
2a + 3a + 4 = 5a + 4
4a + 3a = (4 + 3)a = 7a
You need to solve for a by getting it by itself. You do this by performing the same operation on both sides of the equation 3a + 2 = a -6 subtract 2 from both sides: 3a = a -8 subtract a from both sides: 2a = -8 divide both sides by 2: a = -4
a = 3a + 4 0 = 2a + 4 2a = -4 a = -2
An equation.
It is an equation because: a = 6
yes, one in which a = 6
4a+3a-4 = 10 4a+3a = 10+4 7a = 14 a = 2
-3
The solution for the value of 3a would be -3. The equation would be 6a + 3(4) = 2.
It's a simple linear equation with 'a' as the variable.Here's how to find the solution:3a + 2 = a - 6Subtract '2' from each side of the equation:3a = a - 8Subtract 'a' from each side:2a = -8Divide each side by '2' :a = -4
The first equation factors to (3x + 2)(3x + 4) The second equation factors to (3a + 2b)(3a + 4b)
81(a^4)
Well, if I understand what you're asking, the order of operations is simple and helpful. For example, if you have this equation (with "a" being the variable): 3a - 4 * (18-14) = 20 then you first do parentheses (P in PEMDAS). So, the answer to 18-14 would be 4. Then, since there are no exponents (E), you multiply (M) 4 * 4, which equals 16. Next, since the remaining part of the equation is 3a - 16 = 20, you add (A) 16 to the other side to balance out the equation. Now, all is left is 3a = 36. Now, you just divide (the remaining part of the equation does NOT follow the rule. It goes out of order for some reason). The answer to a is 12. The equation does follow the rules of the order of operations. At the point 3a-16=20, you cannot combine any more terms in the order of addition or subtraction because their aren't any like terms to combine. In algebra, you are solving for the unknown variable, in this case (a). In order to solve for (a), you have to isolate the variable. You do this by balancing out the equation and adding 16 to both sides of the equation, therefore being left with 3a=36. Then you divide by three to further isolate the variable. When left with unlike terms, in essence, you do the order of operations in reverse.
3a + 2b = 4If b = 7, then3a + 2(7) = 43a + 14 = 4Subtract 14 from each side:3a = -10Divide each side by 3:a = -10/3
3a-1=11 Now, you need to keep the equation balanced so whatever you do to one ide of the equation, you MUST do to the other. So the first step is to add 1 to each side of the equation (the equals sign), so we end up with numbers only on one side, and letters only on the other side (or multiples of letters, in this case 3 lots of A...).... 3a-1 = 11 +1 +1 which gives us... 3a+0 =12 or just 3a = 12 Now divide both sides of the equation by 3 to work out what one lot of 'a' is instead of three.... 3a = 12 ÷3 ÷3 a = 4