1,2,3,4,5,7,8,9,10,11,13,14,15,16,17,19,21,21,23,25,26,27,29,31,32,33,34,35,37,38,39,41,43,44,45,46,47,49,50,51,52,53,55,57,58,59,61
There are no Thabit numbers at all on the list you've provided.
First, you add them all up. Then you divide what you've got by how much numbers you've got in the list.
It is impossible to list all of the numbers that are divisible by 3, because the list would go on for eternity. A portion of this list would include the numbers 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, etc.
this is impossible to answer as there are so many numbers the list is infinite.
1,2,3,4,5,7,8,9,10,11,13,14,15,16,17,19,21,21,23,25,26,27,29,31,32,33,34,35,37,38,39,41,43,44,45,46,47,49,50,51,52,53,55,57,58,59,61
All prime numbers are deficient.
Yes.
No. All prime numbers are deficient.
No. From Wikipedia: "The first few deficient numbers are: 1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23, 25, 26, 27, ..." As you can see, the list includes both even and odd numbers. For example, all powers of two are deficient.
All odd numbers with one or two distinct prime factors are deficient. Since 3 and 7 are factors of 63, it must be deficient.
no, 945 is the first abundant odd number though
No, all prime numbers are deficient.
Yes, like all prime numbers.
Yes. All prime numbers are deficient.
No, all prime numbers are deficient.
17 is a deficient number because half the sum its factors is less than 17 [(1 + 17)/2 = 9)]. All odd numbers less than 945 are deficient.