25x2 + 40x + 16 = 25x2 + 20x + 20x + 16 = 5x(5x + 4) + 4(5x + 4) = (5x + 4)(5x + 4) or (5x + 4)2
5x+4+7x
If your equation is 5x-2=4x+4 Then this is how you solve it... 5x-2=4x+4 5x-2+2=4x+4+2 5x=4x+6 5x-4x=4x-4x+6 x=6 Your x=6
The exponential form of -5x-5x-5x-5 can be written as (-5x)^4. This is because when you have the same base raised to multiple exponents that are being multiplied together, you can simplify it by multiplying the exponents. In this case, -5x is the base and 4 is the exponent, resulting in (-5x)^4.
If I understand your question correctly, 4 x 35 x y=140y.
The problem should read: 3x^2 (5x-4) - 5 (5x-4)
(5x)^-4 = 1/(5x)^4 = 1/625x^4 or this can be stated as x^-4/625
The Question is not in a proper form. Is it 4-1+5x or 4-1-5x? Or most likely 4-1= 5x, where x would equal 3/5.
25x2 + 40x + 16 = 25x2 + 20x + 20x + 16 = 5x(5x + 4) + 4(5x + 4) = (5x + 4)(5x + 4) or (5x + 4)2
(x + 4)(x2 - x - 1)
(x + 4)(x2 - x - 1)
(x + 4)(x2 - x - 1)
To do this equation, there would have to be an = in it. If you mean 5x-2y=4, then: 5x-2y=4 -5x -5x = -2y=4-5x Hope this helped!
-40x**6 / -8x**5 = 5x -48x**5 / -8x**5 = 6 -48x**4 / -8x**5 = 6x**-1 5x+6+6x**-1 OR 5x+6+6/x OR (5x**2+6x+6)/x
(x + 4)(x + 1) x = -1 or -4
(5x - 2)(25x2 + 10x + 4)
That factors to 5(x - 4)(x + 4)(x2 + 16)