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What is the x intercept in this equation 5x-2y equals 20?
5x - 2y = 20The x-intercept of a line is the point where its y-value is 0. When y=0, we get 5x = 20, or x=4. This means the coordinates of the x-intercept on this line are (4,0).
5x plus 3y-x plus 10-2y?
5x + (3y-x) + (10-2y) = 5x + 3y - x + 10 -2y = 5x - x + 3y - 2y + 10 = 4x + y +10
What is the x and y intercept of x plus 2y equals 10?
x + 2y = 10At the x-intercept, y=0:x = 10At the y-intercept, x=0 ==> 2y = 10y = 5
What is the x intercept for -x -2y equals 6?
-x -2y = 6At the x-intercept, y = 0.-x = 6x = -6
What is 4x 3y -5x 2y?
I understand this to be 4x + 3y - 5x + 2y. -x + 5y
What is the x and y intercepts for 5x plus 2y equals 20?
The x intercept is the point where y = 0, the y intercept is the point where x =0: For the x intercept: 5x + 2y = 20, but y = 0 => 5x + 0 = 20 => x = 20/5 = 4. So the x intercept is at (4, 0). For the y intercept: 5x + 2y = 20, but x = 0 [The rest of the calculation is left as an exercise for the reader.]
What is the x intercept in this equation 5x-2y equals 20?
5x - 2y = 20The x-intercept of a line is the point where its y-value is 0. When y=0, we get 5x = 20, or x=4. This means the coordinates of the x-intercept on this line are (4,0).
What is the y- intercept and x- intercept for the equation -5x 2y20?
If you mean: -5x+2y = 20 then the x intercept is -4 and the y intercept is 10
What is the y intercept of 5x - 2y equals 20?
write equation in standfrd form y =mx + b where b = y intercept 5x - 2y =20 5x -20 = 2y 5/2 x -10 = y when x = 0 y = -10, the y intercept
What is the X intercept of 5X plus 2Y equals 20?
To find the x-intercept, set y equal to zero in the equation 5x + 2y = 20. Then solve for x: 5x + 2(0) = 20. Simplifying, 5x = 20. Dividing both sides by 5, x = 4. Therefore, the x-intercept is (4, 0).
What is the x intercept to 5x-2y20?
Get in slope intercept form.5X - 2Y = 20- 2Y = - 5X + 20Y = (5/2)X - 10===============zero out the Y(5/2)X - 10 = 0(5/2)X = 10X = 4=====(4, 0) is the intercept point for X
Find the x-intercept to the following linear equation5x - 2y equals 20?
The x-intercept is found when y=0 Therefore 5x - (2 x 0) = 20 : 5x = 20 : x = 20/5 = 4.
Rewrite the equation 5x-2y0 in slope-intercept form?
5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.
What is the x-intercept to the following linear equation 5x-2y equals 20?
Put in function form. 5X - 2Y = 20 - 2Y = - 5X + 20 Y = 5/2X - 10 -------------------------zero out the Y 5/2X - 10 = 0 5/2X = 10 X = 20/5 X = 4 ---------------or, just zero out the Y in original equation 5X - 2(0) = 20 5X = 20 X = 4 -----------either way if only X intercept is wanted.
What is the x-intercept for this linear equation 5x-2y equals 20?
5X - 2Y = 20 -2Y = -5X + 20 Y = 5/2X - 10 set to 0 and solve for X 5/2X - 10 = 0 5/2X = 10 X = 4 My TI-84 graphs and confirms this
What are the x- and y-intercepts for the graph of 5x-2y20?
If you mean: 5x-2y = 20 then y = 2.5x-10 whereas the slope is 2.5 and the y intercept is -10 The x intercept will be at: (4, 0)
Graph the line 5x-10 equals 2y?
2y = 5x - 10Putting into Slope-Intercept form, we have y = 5/2 x - 5. So, the y-intercept is -5 and the slope is 5/2 or 2.5. (x-intercept is 2).
