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The balance is 129178.

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Looking at the amount remaining on the Capital (C) at a rate of r with a repayment of P, there is:

After 1 period: Cr - P

After 2 periods: (Cr - P)r - P = Cr^2 - Pr - P = Cr^2 - P(r + 1)

After 3 periods: ((Cr - P)r - P)r - P = Cr^3 - Pr^2 - Pr - 1 = Cr^3 - P(r^2 + r + 1)

After n periods: Cr^n - P(r^(n-1) + r^(n-2) + ... + r + 1)

The sum in the brackets that multiplies the repayment P is a geometric progression, which has sum:

sum = (r^n - 1) / (r - 1)

→ the amount remaining after n periods is given by

remaining = Cr^n - P (r^n - 1) / (r - 1)

With an APR of 6.5%, the yearly rate is 1 + 6.5/100 = 1.065

Compounded monthly, to get the same amount after one year the monthly rate is 1.065^(1/12) ≈ 1.00526 (a monthly percentage rate of approx 0.526%)

For 20 years, there are 12 x 20 = 240 monthly periods

→ amount remaining ≈ 200,000 x (1.00526)^240 - 1,200 x (1.00526^240 - 1) / (1.00526 - 1) ≈ 129,177.88 ≈ 129,178

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Q: Need Help With Algebra 2 HW ASAP Suppose you have a 200000 home loan with an annual interest rate of 6.5 percent compounded monthly If you pay 1200 per month what balance remains after 20 years?
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