This appears to be a declining arithmetic series. If it is, the next term is 5, because each term is 3 less than the preceding term.
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The 'N'th term is: [ 23 - 3N ].
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The given sequence is decreasing by 3 each time. To find the nth term of the sequence, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term, ( d ) is the common difference, and ( n ) is the term number. In this case, the first term ( a_1 = 20 ) and the common difference ( d = -3 ). So, the nth term of the sequence is ( a_n = 20 + (n-1)(-3) = 23 - 3n ).
Ah, isn't that a lovely sequence you have there? To find the nth term, we can see that the sequence is decreasing by 3 each time. So, if we let the first term be a and the common difference be d, the nth term can be found using the formula a + (n-1)d. Keep exploring those beautiful patterns, my friend!
Oh, dude, it's like a math puzzle. So, the sequence is decreasing by 3 each time. The nth term can be found by starting at 20 and subtracting 3 times (n-1). So, the nth term would be 20 - 3(n-1). Easy peasy lemon squeezy!
The nth term is: 3n+2 and so the next number will be 20
This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.
Tn = 10 + n2
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)