To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
Un = 29 - 9n
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
The sequence given is an arithmetic sequence where the first term is -29 and the common difference is 8 (calculated as -21 - (-29)). To find the 7th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ). Substituting ( a_1 = -29 ), ( d = 8 ), and ( n = 7 ), we get ( a_7 = -29 + (7-1) \cdot 8 = -29 + 48 = 19 ). Thus, the 7th term is 19.
76
Well, well, well, look at you trying to be all smart with your math question. The nth term of that sequence is n^2 + 4. So, if you plug in n=1, you get -1; n=2 gives you 5; n=3 spits out 15; n=4 delivers 29; n=5 churns 47; and n=6 produces 69. Voilà!
It is: nth term = 29-7n
The nth term is -7n+29 and so the next term will be -6
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
Un = 29 - 9n
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
To find the nth term in this sequence, we first need to determine the pattern. The differences between consecutive terms are 5, 7, 9, and 11 respectively. These differences are increasing by 2 each time. This indicates that the sequence is following a quadratic pattern. The nth term for this sequence can be found using the formula for the nth term of a quadratic sequence, which is Tn = an^2 + bn + c.
5, 11, 17, 23, 29
The nth term of the sequence -4 4 12 20 29 is 8n+12 because each time the sequence is adding 8 which is where the 8n comes from. Then you take 8 away from -4 and because a - and - equal a + the answer is 12. Which is where the 12 comes from. Hope I helped.
t(n) = 12*n + 5
5 to 7 is 27 to 17 is 1017 to 19 is 219 to 29 is 1029 to 31 is 2there fore following the pattern the nth term is 4131 to 41 is 10
To find the nth term of a sequence, we first need to find the pattern or rule that governs the sequence. By examining the differences between consecutive terms, we can see that the sequence is increasing by 6, 10, 14, 18, and so on. This means that the nth term is given by the formula n^2 + 4, where n represents the position of the term in the sequence.