number of diagonals = n(n-3)/2
n - number of sides of the polygon
triangle
The diagonals of a square and a rhombus cross at right angles.
It has 0 volume diagonals and 6 face diagonals hence the total number of diagonals are 6
The number of Diagonals in one vertex of a Triangle is 0 (zero)..
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
n * (n-3)/2
Only a square and a rhombus will have all its diagonals bisecting vertices. In other shapes some - but not all - diagonals can bisect vertices.
triangle
In most shapes the diagonals do not bisect one another. It might be possible to answer the question if it were more specific. To start with, shapes with how many sides?
All quadrilaterals (four sided shapes) have 2 diagonals.
not in all shapes.
The diagonals of a square and a rhombus cross at right angles.
It depends on the shape. A square has no diagonals.Improved Answer:-A square has 2 diagonals in common with all other quadrilateralsThe formila is: 0.5*(n2-3n) = diagonals whereas n in the formula represents the number of sides the polygon or shape has
dont no and need to no does anyone no the answer?
square, rhombus and a kite
squares and maybe a rhombus
your ball sack