number of diagonals = n(n-3)/2
n - number of sides of the polygon
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triangle
The diagonals of a square and a rhombus cross at right angles.
It has 0 volume diagonals and 6 face diagonals hence the total number of diagonals are 6
The number of Diagonals in one vertex of a Triangle is 0 (zero)..
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon