It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
By using the polygon diagonal formula or the quadratic equation formula in which in both formulae they work out that the polygon in question has 21 sides.
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
Using the formula 0.5(n^2 -3n) whereas n is number of sides, altogether there are 104 diagonals in a 16 sided polygon
number of diagonals = n(n-3)/2 n - number of sides of the polygon
Number of diagonals in a polygon with n sides is n*(n-3)/2 A pentadecagon has 15 sides, so n = 15 Number of diags = 15*12/2 = 90
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = number of diagonals when n is the number of sides of the polygon
0.5*(n2-3n) where n is equal to the number of sides of the polygon
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
For a 9 sided polygon it is: 0.5*(92-(3*9)) = 27 diagonals
n side polygon has n(n-3)/2 diagonals therefore a hexagon has 9 diagonals
1/2*(n2-3n) where n is the number of sides of the polygon.