other side is 4, hypotenuse is 5
The only thing that can be said about consecutive sides of a quadrilateral is that they meet at a vertex. There is no restriction on the angle, nor on their respective lengths.
There is only one equilateral triangle with a perimeter of 60 units. Its side lengths are integers.
9 is shortest integer side length greater than 17/2
You look at the lengths of the sided of the triangle. If the two lengths are same, the triangle is an isosceles triangle. If all the lengths are same, the triangle is an equilateral triangle. If none of the lengths are same, the triangle is a scalene triangle.
Well the fractional lengths is the length of a fraction
10
The only thing that can be said about consecutive sides of a quadrilateral is that they meet at a vertex. There is no restriction on the angle, nor on their respective lengths.
a rectangle (that is NOT a square) has 4 right angles and consecutive sides of unequal lengths.
Pythagorean triplets.
There is only one equilateral triangle with a perimeter of 60 units. Its side lengths are integers.
A parallelogram with sides whose lengths are half the diagonals of the original quadrilateral.
47, 48, and 49
My friend, you just said the height. :P You just said that it is a 40 feet high cube. Since a cube has equal lengths all over, the width would obviously be 40 feet as well.
The sum of the lengths of two sides of a triangle must be greater than the length of the third so the following eight triangles will do: (1,8,8), (2,7,8), (3,6,8), (3,7,7), (4,5,8), (4,6,7), (5,5,7) and (5,6,6).
9 is shortest integer side length greater than 17/2
There are infinitely many triplets, and in general, they do not have a name. If all three are integers, then they are known as Pythagorean triplets.
IS THIS FOR YOUR HOMEWORK? THE TRICK IS READING THE QUESTION CAREFULLY. CONSECUTIVE EVEN INTEGERS ARE 2 NUMBERS APART, SO IN A RIGHT TRIANGLES SIDES A, B, AND C, A SQUARED + B SQUARED = C SQUARED, AND C = B + 2 6 SQUARED + B SQUARED = [B+2] SQUARED 36 + B SQUARED = B SQUARED + 4B +4 SOLVE FOR B, AND GET 8, SO C WHICH IS [ B+ 2] IS 10. 36 + 64 = 100