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What is the perimeter of 78 feet long and 27 feet wild?
Remember P = 2(l + w) Substituting P = 2(78 + 27) P = 2(105) P = 210 ft.
The perimeter of a rectangular field is P feet The width of the field is 200 feet less than its length In terms of P what is the length of the field in Feet?
P = 2 x (L + W), so L + W = 100 ie P/2 = L + W W = L - 200 so P/2 = L + L - 200 = 2L - 200 therefore L = P/4 + 100
How do you calculate linear feet on a 1600 square foot home for gutters?
You need the perimeter but the area of the home is not sufficient to identify its perimeter. All that can be said is that, in the unlikely event that the home is circular, the perimeter will be 142 feet. For any other shape it will be more. And it can be infinitely more. Suppose the home is rectangular, with length = L feet and width = W feet. Then for an area of 1600 sq feet, W must be 1600/L feet Therefore the perimeter, P = 2*(L+W) = 2L + 3200/L feet. If L = 80 ft, then W = 20 ft and P = 200 ft L = 100 ft then W = 16 ft and P = 232 ft L = 160 ft , W = 10 ft and P = 340 ft You can go further: L = 1600 ft, W = 1 ft P = 3202 ft L = 1.6 million ft, W = 0.001 ft and P = 320000.002 ft L = 1.6 billion ft, W = 0.000001 ft and P = 606060.60.. MILES! As you can see, there is no limit!
What was the perimeter of 25 ft long and 4 feet wide?
24*4=100. So, the perimeter is 100 feet. Or, P=100 ft
How do you use the formula P equals 2L plus 2W?
Perimeter of a rectangle 2L means two sides of length, thus multiply 2W means two sides of width; again multiply four sides around the rectangle and adding the L and W values gives the perimeter. Example: You have a rectangle that is 10 feet long and 6 feet wide. Find perimeter of rectangle that has 4 sides. Perimeter = 2(10 feet) + 2(6 feet) P = 20 feet + 12 feet Perimeter = 32 feet
