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Q: Partner length of a 7 cm line segment?
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Draw a 7 cm line segment Draw all the partner lengths?

7 cm line segament


What are the partner lengths for a segment 8 centimeters long?

The partner lengths for a line segment 8 cm long are 1cm + 7cm, 2cm + 6cm, 3cm + 5 cm, and 4 cm + 4cm


How do you figure out the longest line segment on area 27 cm by 21 cm?

IF it is assumed that the area in question is a rectangle, then the longest line segment that will fit in it is the diagonal. Then, by Pythagoras's Theorem, its length will be sqrt(272 + 212) = 34.21 cm (approx.)However, if it not a rectangle, all bets are off.A parallelogram with sides of 27 and 21 will accommodate a line segment that is a fraction short of 27+21 = 48 cm.


What are the partners lengths for a 7-cm line segment?

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Is the estimated length of line a about 4 cm or 10 cm?

There no information in the question to even hazard a guess. The length of a string (line) could be any measurement.


What is the length of third line on triangle when the other 2 lines are 9 cm?

It can have any length less than 18 cm.


On grid paper draw a line segment with 4.5 cm?

I'd prefer to draw it with a pencil.


How do you represent the fraction four tens using a model or number line?

Draw a line segment 10 cm long. measure the first 4 cm and make that part darker.


One tenth of a line is 5 and a half cm What is the line's total length?

55cm


What is the area of a circle's segment that has a chord length of 30 cm and a diameter of 36 cm showing work?

1. The segment will be enclosed within a sector of radii 18 cm and an arc angle of about 113 degrees. 2. Area of sector: 113/360*pi*18*18 = 319 square cm rounded. 3. Area of segment: 316-area of isosceles triangle contained in the sector = 170 square cm rounded.


What did Pythagoras discover?

He discovered how to find the length of the missing side of a right triangle, so if there was a 5 cm line and a 4 cm line he could tell the length of the other line on a triangle. The answer to the 5 cm by 4 cm would be 3 cm. That is his famous 5, 4, 3 triangle. The formula for it is A squared plus B squared equals C squared.


How do you make square root spiral by paper folding and paper cutting?

First of all draw a line segment that is about 2 cm long between two points P0 and P1. At the one of the outer points, draw another line that is at an angle of 90 degrees from the first line segment. This will cause the new line segment to stand straight on the first segment. Draw another line segment between the not used endpoint of the new line segment, let's call it P2, and the not used endpoint of the first line segment. This will create a triangle. Now on the P2 endpoint, draw another line segment that is again at 90 degrees angle. Repeat the previous steps and you will have created a root spiral.