It can have any length less than 18 cm.
I'd prefer to draw it with a pencil.
55cm
He discovered how to find the length of the missing side of a right triangle, so if there was a 5 cm line and a 4 cm line he could tell the length of the other line on a triangle. The answer to the 5 cm by 4 cm would be 3 cm. That is his famous 5, 4, 3 triangle. The formula for it is A squared plus B squared equals C squared.
Two methods: Draw a straight line using a straight edge Mark one point on it Set a pair of compasses to 6cm With the point on the mark, draw another mark with the compasses on the line. The line between the two marks is a line segment of 6cm. Using a rule marked in cm draw a straight line between the 0cm and 6cm marks along its edge.
7 cm line segament
The partner lengths for a line segment 8 cm long are 1cm + 7cm, 2cm + 6cm, 3cm + 5 cm, and 4 cm + 4cm
IF it is assumed that the area in question is a rectangle, then the longest line segment that will fit in it is the diagonal. Then, by Pythagoras's Theorem, its length will be sqrt(272 + 212) = 34.21 cm (approx.)However, if it not a rectangle, all bets are off.A parallelogram with sides of 27 and 21 will accommodate a line segment that is a fraction short of 27+21 = 48 cm.
Bob saggot
There no information in the question to even hazard a guess. The length of a string (line) could be any measurement.
It can have any length less than 18 cm.
I'd prefer to draw it with a pencil.
Draw a line segment 10 cm long. measure the first 4 cm and make that part darker.
55cm
1. The segment will be enclosed within a sector of radii 18 cm and an arc angle of about 113 degrees. 2. Area of sector: 113/360*pi*18*18 = 319 square cm rounded. 3. Area of segment: 316-area of isosceles triangle contained in the sector = 170 square cm rounded.
He discovered how to find the length of the missing side of a right triangle, so if there was a 5 cm line and a 4 cm line he could tell the length of the other line on a triangle. The answer to the 5 cm by 4 cm would be 3 cm. That is his famous 5, 4, 3 triangle. The formula for it is A squared plus B squared equals C squared.
First of all draw a line segment that is about 2 cm long between two points P0 and P1. At the one of the outer points, draw another line that is at an angle of 90 degrees from the first line segment. This will cause the new line segment to stand straight on the first segment. Draw another line segment between the not used endpoint of the new line segment, let's call it P2, and the not used endpoint of the first line segment. This will create a triangle. Now on the P2 endpoint, draw another line segment that is again at 90 degrees angle. Repeat the previous steps and you will have created a root spiral.