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No, not necessarily. 121 is a palindrome number with 3 digits (odd) and is divisible by 11. So this satisfies the premise, but 101, 111, 131, etc are not divisible by 11.
An example which satisfies the premise does not prove it true, but one which contradicts the premise is enough to prove it false.
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Is 21837 divisible by 6 and 9?
Nope - To be divisible by nine, the sum of the digits must also be divisible by 9 (the digits total 21). Additionally, since it's an odd number - it cannot be divided by 6 !
Which digit is not divisible by two?
odd digits such as 1,3,5,7, and 9.
Is 26871 divisible by 2?
No, 26871 is an odd number. No odd number is divisible by 2.
What odd number is divisible by an even number?
No odd numbers are divisible by even numbers.
IS 8003 divisible by 11?
If the sum of the digits in the odd positions starting from the ones digit less the sum of the digits in the even positions (starting with the 10s digit) is divisible by 11, then so is the original number. for 8003: odd position digits: 3 + 0 = 3 even position digits: 0 + 8 = 8 3 - 8 = -5 which is not divisible by 11, so 8003 is NOT divisible by 11.
Can you factorise every palindrome with odd number of digits?
No. 101 is prime.
The factor of every palindrome with an even number of digits?
Every palindrome with an even number of digits is divisible by 11. The easiest way to see this is to recall the divisibility rule by 11: if a number X is written as ABCDEFG... (here A,B,C, ... are digits), then it's divisible by 11 if and only if the sum A-B+C-D+E-F+G-... is divisible by 11. In a palindrome with an even number of digits, each digit will appear in an odd position and in an even position, so when we calculate this sum, it will be added once and subtracted once, canceling. Since all the digits cancel, the sum A-B+C-D+... will be 0, which is divisible by 11. So the original number ABCD....DCBA was also divisible by 11.
What digits divisible by 4?
4 and all of its multiples are divisible by 4. They end in even digits. No number that ends in an odd digit is divisible by 4.
What is an odd number with four digits that is divisible by nine?
ez.....9999
What is the smallest number divisible by 7 and 6 and has two odd digits?
336
What is the smallest number which is divisible by 7 and 6 and has two odd digits?
To find the smallest number divisible by 7 and 6 with two odd digits, we need to consider the least common multiple (LCM) of 7 and 6, which is 42. The smallest two-digit odd number is 11. Therefore, the smallest number that meets all these criteria is 11 x 42, which equals 462.
How is a number divisible by 8?
If the number formed by the last three digits is divisible by 8. This requires that: if the digit in the hundreds place is even, the last two digits must form a number divisible by 8 and if the digit in the hundreds place is odd, the last two digits must form a number divisible by 4 but not by 8.
How many six digit numbers are there in which no digit is repeated even digits appeared in the even places and odd digits in the odd places and the number is divisible by 4?
There are 5760 such numbers.
Is 21837 divisible by 6 and 9?
Nope - To be divisible by nine, the sum of the digits must also be divisible by 9 (the digits total 21). Additionally, since it's an odd number - it cannot be divided by 6 !
What is the rule for numbers divisible by 11?
The sum of the digits in odd position minus the sum of the digits in even position is divisible by 11.
Which digit is not divisible by two?
odd digits such as 1,3,5,7, and 9.
IS 8003 divisible by 11?
If the sum of the digits in the odd positions starting from the ones digit less the sum of the digits in the even positions (starting with the 10s digit) is divisible by 11, then so is the original number. for 8003: odd position digits: 3 + 0 = 3 even position digits: 0 + 8 = 8 3 - 8 = -5 which is not divisible by 11, so 8003 is NOT divisible by 11.
