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I am working on the same exact proof right now and i am lost

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15y ago

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Does a square cross diagonally at right angles?

It's fairly trivial to prove that the angles formed by the angle bisectors of any rhombus (including squares) are right angles.


If two angle bisectors of a triangle are congruent then prove that triangle is isosceles?

The two angle bisectors of a triangle are congruent the those two angles are congruent. The angles are bisected the same meaning that the whole and half angle are the same. For example if they are bisected at the whole angle 50 each, then each half is 25. The bisectors really don't mean anything and all you need is 50 to know it's isosceles. 50 and 50 is 100 and the left over for the last angle is 80 adding to 180. AND overall any 2 congruent angles in a triangle have the same congruent legs making it isosceles.


Angle bisector of a triangle?

The angle bisectors of a triangle are the lines which cut the inner angles of a triangle into equal halves. The angle bisectors are concurrent and intersect at the center of the incircle.


How The bisectors of any 2 consecutive angles of a parallelogram intersect at right angle?

Yes.


What is the angle bisector concurrency theorem?

the definition of an angle bisector is a line that divides an angle into two equal halves. So you need only invoke the definition to prove something is an angle bisector if you already know that the two angles are congruent.


Prove that the bisectors of 2 adjacent supplementary angles include a right angle?

∠DAB + ∠EBA = 180� ⇒ 2∠CAB + 2∠CBA = 180� (Using (1) and (2)) ⇒ ∠CAB + ∠CBA = 90� In ∆ABC, ∠CAB + ∠CBA + ∠ABC = 180� (Angle sum property) ⇒ 90� + ∠ABC = 180� ⇒ ∠ABC = 180� - 90� = 90� Thus, the bisectors of two adjacent supplementary angles include a right angle.


How The bisectors of any 2 consecutive angles of a parallelogram intersect at right angles?

I expect "consecutive angles" are any pair that aren't opposite. Since they are co-interior angles between parallel lines, they are supplementarty (i.e. total 180 deg). When you bisect them, the bisectors join to form a triangle. Two of its angles are halves of the "consecutive angles", and so they total half of 180 deg, which is 90 deg. Hence the third angle is 90 deg (to give angle sum of the triangle as 180 deg), so the bisectors are perpendicular.


What type of triangle has 3 angle bisectors that are also perpendicular bisectors?

Oh, what a happy little question! The type of triangle you're describing is called an equilateral triangle. In an equilateral triangle, all three angles are equal, and the angle bisectors are also the perpendicular bisectors of the sides, creating a beautiful balance in the painting of geometry.


The intersection of the angle bisectors of a triangle?

The intersection of the angle bisectors of a triangle is called the incenter. It is equidistant from the sides of the triangle and can be constructed by drawing the angle bisectors of the triangle's angles. The incenter is the center of the incircle, which is the circle inscribed within the triangle.


Angle that forms a linear pair with one of the interior angles of a triangle?

Exterior Angles


At what point are the angle bisectors of a triangle concurrent?

Angle bisectors intersect at the incenter which is equidistant from the sides


What is the intersection of the angle bisectors called?

The 3 angle bisectors of a triangle intersect in a point known as the INCENTER.