PR = 110 because... P = 10, Q = 2... therefore R = 11
3p-pq 2pr factorized = 1
True
(5p - 4q)/pq
p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
6
8(p + q)(p^2 - pq + q^2)
If M P and Q are collinear and MP plus PQ equals MQ then P is between M and Q.
PR = 110 because... P = 10, Q = 2... therefore R = 11
p x q pq
P x Q
p = (2 + 5i)q = (6 - i)pq = (2 + 5i) (6 - i)pq = 12 + 30i - 2i - 5i2pq = 12 + 28i + 5pq = 17 + 28iIts the same as multiplying polynomials. Just multiply all the combinations of terms, group, and simplify.
Only if p and q are DIFFERENT primes.
6p - pq 7pr factorizing = -1
In algebra, you could write it as simply 'pq'.
True
pq